I had been using the Show-InstallationWelcome function with great success, however the existing script is not good enough in following scenario:
I need to kill only 1 particular instance of process that is run from 1 particular location, leaving the other processes with the same name but that are being run from other locations intact. No defer enabled.
Show-InstallationWelcome -CloseApps “deploytoolkit” -PersistPrompt -CloseAppsCountdown 600
Here is an example:
2 processess named deploytoolkit.exe are running and Windows Task Manager shows “Image Path Name”:
C:\Program Files (x86)\APP\deploytoolkit.exe
C:\Program Files\Common Files\APP\deploytoolkit.exe
I need to end only deploytoolkit.exe that is launched from path “C:\Program Files\Common Files\APP\deploytoolkit.exe” while leaving the other one intact.
Is there any way to modify the Show-InstallationWelcome function to achieve this? I have tried several things, but could not get it to work properly. Any help is much appreciated!